Question

Exterior angle of pentagon are in ratio 6:3:4:3:2 find all its interior angles >

Answer 1

Answer:

let the exterior angles be 6x,3x,4x,3x,2x

we know that sum of all exterior angles of a Pentagon is 360°

=6x+3x+4x+3x+2x=360

=18x=360

=X=360/18

=20°

exterior angles = 6x,3x,4x,3x,2x

=6*20,3*20,4*20,3*20,2*20

=120°,60°,80°,60°,40°

each interior angle=180-each exterior angle

=180-120=60°

=180-60=120°

=180-80=100°

=180-60=120°

=180-40=140°

Answer 2

Answer:

60°,120°,100°,120°,140°