External and internal radii of a lead pipe are respectively 5 cm and 4 cm. If on melting the pipe a solid right circular cylinder of same height be made, find the radius of the solid cylinder.
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Answered by
5
Hi there☺
⬇SOLUTION⬇
External radius of the pipe, R = 5 cm and internal radius of the pipe, r = 4 cm
Let the height of the pipe = h cm
Volume of lead in the pipe
= pi × h (R^2 - r^2)
= pi × h (5^2 - 4^2) cm^3
= 9 pi × h cm^3
Let radius of the solid cylinder = x cm
Then, volume of solid cylinder = pi × r^2 × h
= pi × x^2 × h cm^3
Clearly, pi × x^2 × h = 9 × pi × h
or
x^2 = 9
Therefore, x = root under 9 = 3 cm
Hence radius of the solid cylinder = 3 cm
__________________________
Hope it helps ✌
⬇SOLUTION⬇
External radius of the pipe, R = 5 cm and internal radius of the pipe, r = 4 cm
Let the height of the pipe = h cm
Volume of lead in the pipe
= pi × h (R^2 - r^2)
= pi × h (5^2 - 4^2) cm^3
= 9 pi × h cm^3
Let radius of the solid cylinder = x cm
Then, volume of solid cylinder = pi × r^2 × h
= pi × x^2 × h cm^3
Clearly, pi × x^2 × h = 9 × pi × h
or
x^2 = 9
Therefore, x = root under 9 = 3 cm
Hence radius of the solid cylinder = 3 cm
__________________________
Hope it helps ✌
Answered by
8
hey
here is ur answer
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