Question

f=2π√l/g where f is the frequency. Is this dimensionally correct or not​

Answer 1

Answer:

Wait...... I am giving you a attachment... see it

Answer 2

DIMENSIONAL ANALYSIS:

• f = 2π√(l/g)

LHS :

$\bigg[f\bigg] = \bigg[{T}^{ - 1} \bigg]$

RHS:

$\bigg[2\pi \sqrt{ \dfrac{l}{g} } \bigg]$

$= \bigg[ \sqrt{ \dfrac{l}{g} } \bigg]$

$= \bigg[ \sqrt{ \dfrac{L}{L{T}^{ - 2} } } \bigg]$

$= \bigg[ \sqrt{ \dfrac{1}{{T}^{ - 2} } } \bigg]$

$= \bigg[ \dfrac{1}{{T}^{ - 1} } \bigg]$

$= \bigg[ {T}^{1}\bigg]$

$\boxed{ \bf \: LHS \neq RHS}$

So, the Equation is not dimensionally correct.