F 3x+k , 2x+9 and x+13 are the three consecutive term of AP . Find the value of K
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since he series is in AP.
2b=a+c
here a=3x+k...b=2x+9...c=x+13
on solving u get 4x+18=4x+k+13
then 18=k+13
k=5
2b=a+c
here a=3x+k...b=2x+9...c=x+13
on solving u get 4x+18=4x+k+13
then 18=k+13
k=5
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