Question

F body having initial velocity zero is moving with uniform acceleration 8 m/sec , the distance travelled by in fifth second will be

Answer 1

given,
initial velocity(u)=0
acceleration (a)= 8m/s sq
time(t) =5 s
From 2nd equation of motion,we get,
S= ut+1/2 at²
= 0×5+1/2×8×5²
= 100m
therefore,distance travelled =100m

Answer 2

Answer:

36m

Explanation:

distance travelled in 5 sec= 1/2at^2

=1/2×8×(5)^2=100m in 5 sec

distance travelled in 4 sec=1/2at2

=1/2×8×(4)^2= 64m in 4 sec

100-64=36m in 5th sec