Question

f distance b|n parallel line 4x+6y+4=0 and 4x+6y+5=0

Answer 1

Heya!!!

Distance between two // lines =

5 -4 / √ ( 4² + 6² )

1 / √ ( 52 )

Have a nice time.

Answer 2

Formula :

Let, the two parallel lines are

ax + by + c1 = 0 ...(i)
ax + by + c2 = 0 ...(ii)

Then, the distance between the two lines be
= { mod value of (c1 - c2) } / √(a² + b²)

Solution :

The given two lines are

4x + 6y + 4 = 0
4x + 6y + 5 = 0

So, the required distance between the parallel lines be
= { mod value of (4 - 5) } / √(4² + 6²)
= { mod value of ( - 1 ) } / √(16 + 36)
= 1/√52
= 1/(2√13) units

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