f =ma.i wan derivation of this formula
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✔️Newton’s second law of motion states that: the net external force applied on an object is directly proportional to the rate of change of linear momentum of the object.
✔️Let the external force be F, initial velocity be u ,final velocity be v, the time interval be t.
=> p1(initial momentum ) = mu
p2(final momentum )= mv
Therefore, (rate of change of momentum)
Δp=(mv-mu)/t
According to newton’s IInd law , F α Δp
=>F =k * (mv-mu)/t { k is a constant }
In S.I.Units, the value of k is 1
So. F= m(v-u)/t
=> F = ma
Hence proved
#Be Brainly✌️
✔️Newton’s second law of motion states that: the net external force applied on an object is directly proportional to the rate of change of linear momentum of the object.
✔️Let the external force be F, initial velocity be u ,final velocity be v, the time interval be t.
=> p1(initial momentum ) = mu
p2(final momentum )= mv
Therefore, (rate of change of momentum)
Δp=(mv-mu)/t
According to newton’s IInd law , F α Δp
=>F =k * (mv-mu)/t { k is a constant }
In S.I.Units, the value of k is 1
So. F= m(v-u)/t
=> F = ma
Hence proved
#Be Brainly✌️
hanumanthusravani26:
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Answered by
3
According to the Newton's Second Law, that states that the net external force acting upon a body is proportional to the rate of change of linear momentum.
From this statement we can write that,
F(net) =( mv - mu )/ t
= m (v-u)t
And now we can know that the rate of change of velocity is acceleration of that body
Thus,
F(net) = mass * acceleration.
From this statement we can write that,
F(net) =( mv - mu )/ t
= m (v-u)t
And now we can know that the rate of change of velocity is acceleration of that body
Thus,
F(net) = mass * acceleration.
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