f:R-{0} = R ,f(x) =x²+4√x+3 then find f(4),f(16)
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Answered by
1
Step-by-step explanation:
f:R1→(4,∞)
f(x)=x2+4
f(x1)=f(x2)
x12+4=x22+4
x1=x2 f(x) is on-one.
f(x)=x2+4
y=x2+4
x2=y−4
x=y−4
f(x)=x2+4
f(x)=(y−4)2+4
f(x)=y−4+4
f(x)=y
f(x) is onto function.
So,f(x) is bijective, Hence it is invertible
f(x)=x2+4
y=x2+4
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Answered by
3
Answer:
√X-4 is the answer.
Formula us written in the photo.
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