Question

F R E E P O I NT

again 50 point​

Answer 1

Answer:

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Answer 2

Answer:

(i) Here, Principal (P) = Rs. 80000, Time (n) = 1\ \frac{1}{2} years, Rate of interest (R) = 10%

Amount for 1 year (A) = P\left(1+\frac{R}{100}\right)^n

= 80000\left(1+\frac{10}{100}\right)^1

= 80000\left(1+\frac{1}{10}\right)^1

= 80000\left(\frac{11}{10}\right)^1

= Rs. 88,000

Interest for \frac{1}{2} year = \frac{88000\times10\times1}{100\times2}

= Rs. 4,400

Total amount = Rs. 88,000 + Rs. 4,400 = Rs. 92,400

(ii) Here, Principal (P) = Rs. 80,000

Time(n) = 1\ \frac{1}{2} year = 3 years (compounded half yearly)

Rate of interest (R) = 10% = 5% (compounded half yearly)

Amount (A) = P\left(1+\frac{R}{100}\right)^n

= 80000\left(1+\frac{5}{100}\right)^3

= 80000\left(1+\frac{1}{20}\right)^3

= 80000\left(\frac{21}{20}\right)^3

= 80000\times\frac{21}{20}\times\frac{21}{20}\times\frac{21}{20}

= Rs. 92,610

Difference in amounts

= Rs. 92,610 – Rs. 92,400 = Rs. 210

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Explanation:

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