f: R—>R,f(x)=x³, Is the given function one-one or onto?
Answers
Answered by
3
I hope it is the answer
Attachments:
Answered by
0
f : R -----> R ,f(x) = x³
condition of one - one function :
if we take two different points x1 and x2 from domain of given function , f(x).
if we solve f(x1) = f(x2) , we get x1 = x2 then, f(x) is definitely an one one function.
let's take two different points x1 and x2
now, f(x1) = x1³
f(x2) = x2³
so, f(x1) = f(x2)
x1³ = x2³
x1 = x2
hence, it is clear that function is one - one.
condition of onto function :
co - domain = range
let's find range ,
y = x³
x = f(y) = y⅓
here is no any point where f(y) will be undefined.
hence, domain of f(y) belongs to R
so, range of f(x) belongs to R
hence, co-domain = range
so, f(x) is onto function.
hence, function,f(x) is one - one as well as onto.
condition of one - one function :
if we take two different points x1 and x2 from domain of given function , f(x).
if we solve f(x1) = f(x2) , we get x1 = x2 then, f(x) is definitely an one one function.
let's take two different points x1 and x2
now, f(x1) = x1³
f(x2) = x2³
so, f(x1) = f(x2)
x1³ = x2³
x1 = x2
hence, it is clear that function is one - one.
condition of onto function :
co - domain = range
let's find range ,
y = x³
x = f(y) = y⅓
here is no any point where f(y) will be undefined.
hence, domain of f(y) belongs to R
so, range of f(x) belongs to R
hence, co-domain = range
so, f(x) is onto function.
hence, function,f(x) is one - one as well as onto.
Similar questions