Question

F the radii of the circular ends of a truncated conical bucket which is 45cm high be 28cm and 7cm then the capacity of the bucket in cabin CM is (use
$\pi = \frac{22}{7}$

Answer 1

v=1/3πr^2h=1/3*22/7*7^2*45=2310CM

Answer 2

The answer is given below:-