Question

f velocity is equal to time taken (I
then radius (R) will be equal to​

Answer 1

Answer:

For circular motion, the radial acceleration, ar is given by Rv2, and the tangential acceleration, at is given by dtdv

Since these accelerations are equal, so Rv2=dtdv

Hence,(v2R)dv=dt

Upon integration

∫v2Rdv=∫dt

vR=t+C

To evaluate integration constant C

Put v=v0 at t=0

Therefore, C=−v0R

The relation between v and t is ,

vR=t−v0R

t=R[v0.vv−v0]

Now, v=dtds, 

where, s id the length of the arc covered by the particle as it moves in