f(x)= 1+cotx/1-cotx find f'x
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Step-by-step explanation:
`f(x) = (sqrt2 cos x - 1)/(cot x - 1) ; x != pi/4`
`f(pi/4) = f(pi^-/4) = f(pi^+/4)`
`lim_(x->pi/4) (sqrt2 cos x - 1)/(cot x - 1) = 0/0`
`lim_(x->pi/4) (sqrt2 sin x)/(cosec^2 x) `
`= (sqrt2 xx 1/sqrt2)/2 = 1/2`
`f(pi/4) = 1/2`
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