Question

f(x)=√16-x² find domain and range​

Answer 1

x=4

Since f(x) here = 0 .

100% correct.

Brainliest .

Answer 2

Step-by-step explanation:

D=(−4,4),x∣−4≤x≤4

R=(0,4) , y|0\leq y\leq 4R=(0,4),y∣0≤y≤4

Step-by-step explanation:

Given : The function f(x)=\sqrt{16-x^2}f(x)=

16−x

2

To find : The domain and range of the function?

Solution :

Domain of the function is where the function is defined

The given function f(x)=\sqrt{16-x^2}f(x)=

16−x

2

To find domain,

\sqrt{16-x^2}=0

16−x

2

=0

16-x^2=016−x

2

=0

x^2=16x

2

=16

x=\pm4x=±4

So, Domain of the function is D=(-4,4) , x|-4\leq x\leq 4D=(−4,4),x∣−4≤x≤4

Range is the set of value that corresponds to the domain.

f(x) is maximum at x=0 , f(x)=4

f(x) is minimum at x=4 , f(x)=0

So, Range of the function is R=(0,4) , y|0\leq y\leq 4R=(0,4),y∣0≤y≤4