f(x)=√16-x² | x | ≤ 4,Find the maximum and minimum value of the given function.
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Dear Student:
F(x)=√16-x² | x | ≤ 4
For,maximum and minimum
We will find df/dx and then equate to zero.
And then again proceed for second derivative and see it is negative or positive.
If it is positive then f will be minimum
And if negative then f maximum
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In the attachment I have answered this problem.
The solution is simple and easy to understand.
See the attachment for detailed solution.
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