Question

f(x)=sinx+cosx x ∈ [0,2π],Find the maximum and minimum value of the given function.

Answer 1

Dear Student:

F(x)=sinx+cosx x ∈ [0,2π]

For,maximum and minimum  

We will find df/dx and then equate to zero.

And then again proceed for second derivative and see it is negative or positive.

If it is positive then f will be minimum

And if negative then f maximum

But here we know maximum and minimum value of sinx.

So, we don't need to differentiate it.

See the attachment:

Answer 2

In the attachment I have answered this problem.

The solution is simple and easy to understand.

See the attachment for detailed solution.