f(x)=2x^3+3x^2-11x-6 then find the value of f(-2)
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f(x)=2x^3+3x^2-11x-6
f(-2 )=2(-2)^3+3(-2)^2-11(-2)-6
= 2× -8 + 3×4 -22 -6
= -16 +12-28
= -32
is the answer buddy
Answered by
0
Given that :
f(x) = 2x³+3x²-11x-6
On taking the value of x = -2 :
f(-2) = 2(-2)³+3(-2)²-11(-2)-6
=> f(-2) = 2×(-8)+3×4+22-6
=> f(-2) = -16+12+16
=> f(-2) = 12
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