Question

f(x)=2x^3+3x^2-11x-6 then find the value of f(-2)​

Answer 1

f(x)=2x^3+3x^2-11x-6

f(-2 )=2(-2)^3+3(-2)^2-11(-2)-6

= 2× -8 + 3×4 -22 -6

= -16 +12-28

= -32

is the answer buddy

Answer 2

Given that :

f(x) = 2x³+3x²-11x-6

On taking the value of x = -2 :

f(-2) = 2(-2)³+3(-2)²-11(-2)-6

=> f(-2) = 2×(-8)+3×4+22-6

=> f(-2) = -16+12+16

=> f(-2) = 12

@ItsChampion ✌️