Question

F(x) = 3x-3 and
9 g(x)=√2x+1
Evalte 2 Fg (4)​

Answer 1

Step-by-step explanation:

$9g(x) = \sqrt{2x} + 1 \\ 9(g(4)) = \sqrt{2 \times 4} + 1 \\ 9(g(4)) = \sqrt{8} + 1 \\ g(4) = \frac{ \sqrt{8} + 1 }{9}$

$f(x) = 3x - 3 \\ f(g(4)) = 3 \times ( \frac{ \sqrt{8} + 1}{9} ) - 3 \\ f(g(4)) = \frac{ \sqrt{8} - 1 }{3} - 3$

$2f(g(4)) = \frac{2}{3} (2 \sqrt{2} - 1) - 6$