Question

f(x)=e^x & g(x)=log x , find (f-g)(1)​

Answer 1

SOLUTION

GIVEN

$\sf{f(x) = {e}^{x} \: \: \: and \: \: \: g(x) = \log x}$

TO DETERMINE

$\sf{(f - g)(1)}$

EVALUATION

Here it is given that

$\sf{f(x) = {e}^{x} \: \: \: and \: \: \: g(x) = \log x}$

$\therefore \: \sf{f(1) = {e}^{1} = e}$

$\therefore \: \sf{g(1) = \log 1 = 0}$

Hence

$\sf{(f - g)(1)}$

$= \sf{f(1) - g(1)}$

$\sf{ = e - 0}$

$= \sf{e}$

FINAL ANSWER

$\sf{(f - g)(1) = e}$

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