Question

F-x equation of a body in SHM is F + 4x=0 Here, F is in newton and x in meter. Mass of the body is 1 kg. Find time period of oscillations.

Answer 1

Answer:

F + 4x = 0

F= -4x ................................(i)

negative sign indicates its a restoring force and thus is a SHM

w = (F/x)^1/2

thus, w= (4)^1/2

w= 2

now, we know that, T= (2*3.14)/w

thus, T= 3.14 seconds

HERE, W= ANGULAR FREQUENCY

            F = FORCE

            T = TIME PERIOD

Explanation:

Answer 2

The time period of oscillations is 3.14 seconds

Mass of the body = 1 kg (Given)

Equation of a body in SHM = F + 4x = 0 (Given)

where F = newton and x = m

The given equation can be written as  

F = − 4x

Substituting with SHM's standard equation -

F = -Kx

K = 4N/m

Thus,

T = 2π √ m/k

= 2π √ 1/4

= π seconds or 22/7 seconds

= 3.14 seconds