f(x)=f(x-1) +f(x+1) . if f(3)=2 and f(1) =0, Find the value of f(40)
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Answer:80
Step-by-step explanation:f(x) =f(x-1)+(x+1)
When f(x) =f(40)
Then,
F(40)=(40-1)+(40+1)
F(40)=39+41
F(40)=80.
If I'm wrong please endeavor to correct.
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