Math, asked by akvaman9, 8 months ago

f(x)=f(x-1) +f(x+1) . if f(3)=2 and f(1) =0, Find the value of f(40)

Answers

Answered by aeeshaolajumoke313

0

Answer:80

Step-by-step explanation:f(x) =f(x-1)+(x+1)

When f(x) =f(40)

Then,

F(40)=(40-1)+(40+1)

F(40)=39+41

F(40)=80.

If I'm wrong please endeavor to correct.

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