Question

the roots ofx2-4x-12=0 are​

Answer 1

x^2-4x-12 = 0

x^2 - 6x+2x-12 = 0

x( x-6)+2 ( x-6) =0

(x+2) ( x-6) = 0

so , x= -2 ,x= 6

Answer 2

hope it helps uh

Step-by-step explanation:

x^2-4x-12 = 0

x^2 - 6x+2x-12 = 0

x( x-6)+2 ( x-6) =0

(x+2) ( x-6) = 0

so , x= -2

x= 6