Math, asked by ankitbharti373, 10 months ago

f(x), g(x) and h(x) are defined for x N as follows:
f(x)= 3x + 2, g(x)= 4x + 1, h(x)= 5x + 3.
which of the following can be expressed as all the three functions f, g and h

A. 30x + 17
B. 60x + 41
C. 30x + 13
D. 60x + 53

Answers

Answered by amitnrw
0

30x + 17  =  2f(x)  + g(x)  +  4h(x)  ,  30x + 13 = 3f(x)  + 4g(x)  + h(x)    if f(x)= 3x + 2, g(x)= 4x + 1, h(x)= 5x + 3

Step-by-step explanation:

a * f(x) + bg(x)  + c h(x)

= a( 3x + 2)  + b(4x + 1)  + c(5x + 3)

= x(3a + 4b  + 5c)  + 2a + b  + 3c

Equating with 30x + 17

3a + 4b + 5c  = 30   Eq1

2a  + b   + 3c  = 17   Eq2

4 * eq2 - Eq1

=> 5a + 7c  = 38

c = 4    a  = 2

2 (2)  + b + 3(4) = 17

=> b = 1

30x + 17  =  2f(x)  + g(x)  +  4h(x)

Similarly for 60x + 41

3a + 4b + 5c  = 60   Eq3

2a  + b   + 3c  = 41   Eq4

4 * eq4 - Eq3

=> 5a + 7c  = 104

a = 18   c  = 2      => b = -1

a = 4    c = 12     => b = -3

( not considering -ve  Values)

Similarly for 30x + 13

3a + 4b + 5c  = 30   Eq5

2a  + b   + 3c  = 13   Eq6

4 * eq6 - Eq5

=> 5a + 7c  = 22

a = 3   c  = 1      => b = 4

=> 30x + 13 = 3f(x)  + 4g(x)  + h(x)

Similarly for 60x + 53

3a + 4b + 5c  = 60   Eq7

2a  + b   + 3c  = 53   Eq8

4 * eq8 - Eq7

=> 5a + 7c  = 152

a = 29   c  = 1      => b = -8

a = 15   c  = 11      => b = -10

a = 1    c = 21    => b = -12

( not considering -ve  Values)

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