Question

⚡Find value of 'k'⚡

✨(i) 3x² + 2kx – 3 = 0, x = -1/2✨​

Answer 1

✏ Answer :

$3x {}^{2} + 2kx - 3 = 0 \\ 3 ( - \frac{ 1}{2} ) {}^{2} + 2k( - \frac{1}{2}) - 3 = 0 \\ 3( \frac{1}{4} ) + 2k( \frac{1}{4} ) - 3 = 0 \\ \frac{3}{4} + \frac{k}{2} - 3 = 0 \\ \frac{3 + 2k -12}{4} = 0 \\ -9 + 2k = 0 \\ k = \frac{ 9}{2}$

Answer 2

HEYA HERE IS YOUR ANSWER

X = -1/2

3 × 1/2 × 1/2 +K × 1/2 - 3 = 0

3/4 + K/2 - 3 = 0

3/4 + 2K/4 -12/4 = 0 (BY TAKING L.C.M.)

(-9+2k)/4 =0

-9 + 2k = 4 × 0

2k = +9

k = 9 / 2

k = 4.5

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