Question

f=(x/linear density)+y ,where f=force then find dimension of x and y​

Answer 1

Explanation:

dimension of f=[MLT^-2]

dimension of linear density=[ML^-3]

now, according to the principle of homogeneity of dimension, only those quantities can be added or subtracted which has same dimensions..

so,

dimension of x=[MLT^-2][ML^-3]

=[M²L^-1T^-2]

dimension of y=dimension of f=[MLT^-2]

Answer 2

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