f(x)=log(1+ax)-log(1-bx)/x
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hello users ....
here
F(x)=log(1+ax)-log(1-bx)/x
now we have to simplify it
Solution :-
F(x)=log(1+ax) - log (1-bx)/x =log x(1+ax)/(1-bx)
= log(x)+log (1+ax)/(1-bx)answer
hope it helps...
here
F(x)=log(1+ax)-log(1-bx)/x
now we have to simplify it
Solution :-
F(x)=log(1+ax) - log (1-bx)/x =log x(1+ax)/(1-bx)
= log(x)+log (1+ax)/(1-bx)answer
hope it helps...
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