f (x) = sec 3x then find f'(x)
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Given, f(x)=sec(3x)
We get f ′ (x)=3sec(3x)tan(3x)
Therefore, we get f ′ = (3π/4)=
3 sec (9π/4) tan (9π/4)
3 sec (π/4) tan (π/4)
3×√2×1
3×√2
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