Question

f(x) =$\tt{\frac{1}{x-1}}$ Then find f[f(3)]​

Answer 1

$\huge\sf{ \underline{ \underline{Question}}}$

• Find value of f[f(3)]

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• -2

$\huge\sf{ \underline{ \underline{Solution}}}$

$\sf{Firstly\:we\:will\:find\:f(3)}$

$\sf{ \boxed{f(x)\:=\:\frac{1}{x-1}}}$

$\sf{For\:f(3)\:put\:x\:=\:3 }$

$\mapsto\sf{f(3)\:=\:\frac{1}{3-1}}$

$\mapsto\sf{f(3)\:=\:\frac{1}{2}}$

$\sf{ \boxed{f[f(3)]\:=\:\frac{1}{x-1}}}$

$\sf{Put\:value\:of\:f(3)}$

$\mapsto\sf{f[f(3)]\:=\:\frac{1}{\frac{1}{2}-1}}$

$\mapsto\sf{f[f(3)]\:=\:\frac{1}{\frac{-1}{2}}}$

$\mapsto\sf{f[f(3)]\:=\: -2}$

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$\sf{ \underline{ \underline{So\:value\:of\:f[f(3)]\:is\:-2}}}$

Answer 2

Answer:

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$\bf\blue{The\: AnsweR\:will\:be\:(-2)}$

Check the above attachment!

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