Math, asked by gopesh69, 1 month ago

f(x) = x^3 - 6x² + 11x – 6, g(x) = x² – 3x+2​

Answers

Answered by manasanagireddy16
6

As f(1),f(2) is Zero . Therefore g(x) is the factor of polynomial f(x)

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Answered by vidhibadotra0
3

Answer:

g(x)=x^2-3x+2

=x^2-2x-x+2

=x(x-2) -1(x-2)

=(x-1) (x-2)

So,we get two value of x

that is (x-1) (x-2)

f(x)=x^3-6x^2+11x-6 (x=1)

f(1) =(1)^3-6(1)^2+11(1)-6

=1-6(1)+11-6

=1-6+11-6

=(-5)+11-6

=6-6

f(1) =0

f(x)=x^3-6x^2+11x-6 (x=2)

f(2)=(2)^3-6(2)^2+11(2)-6

=8-6(4)+22-6

=8-24+22-6

=(-16)+22-6

=6-6

f(2)=0

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