Question

f(x)=x^3+kx^2-4x-12........ if f(-2)​

Answer 1

Answer:

put the value of x= -2

= -2^3+k(-2)^2-4(-2)-12

= -8+k(4)+8-12

= -8+4k-4

= 4k-12

= 4k = 12

= k = 12/4

= k = 3

Answer 2

Answer:

5x2 - 4x +2 + k(4x2-2x-1) =05x2-4x+2+4k×2-2kx-k=0(5+4k)×2-(4+2k)x-k +2=0 here, a=(5+4k), b= -(4+2k, c= -k+2

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