Question

f(x) = x²+6x+10 find f(2)+f(-2).
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Answer 1

Step-by-step explanation:

f (2) + f (-2) = 28

Explination :- f (x) = x^2+6x+10

1 ) f (x )= 2

: - f (2)= (2)^2+6 (2) +10

= 4+12+10

= 26 .

2) f (x) = (-2)

:- f (-2) = (-2)^2+6 (-2)+10

= 4 -12 +10

= 2

* f (2)+f (-2) = 26 + 2 = 28

Answer 2

Given:

A quadratic function f(x) = x²+ 6x + 10.

To Find:

The value of f(2) + f(-2).

Solution:

1. The given quadratic function is f(x) = x²+ 6x + 10.

2. The value of the function at x = 2 is,

=> f(2) = 2²+ 6(2) + 10,

=> f(2) = 4 + 12 + 10,

=> f(2) = 26.

3. The value of the function at x = -2 is,

=> f(-2) = (-2)²+ 6(-2) + 10,

=> f(-2) = 4 + (-12) + 10,

=> f(-2) = 14 - 12,

=> f(-2) = 2.

4. The value of f(2) + f(-2) is,

=> f(2) + f(-2) = 26 + 2 = 28.

Therefore, the value of f(2) + f(-2) is 28.