Question

f you can't give answer of my questions then you all are donkeys​

Answer 1

Answer:

Answer is 1

Have a nice day

Answer 2

Answer:

1 is the answer

Step-by-step explanation:

${\small{\sf{ \bigg( \dfrac{x^{a+b}}{x^c} \bigg)^{a-b} × \bigg( \dfrac{x^{b+c}}{x^a} \bigg)^{b-c} × \bigg( \dfrac{x^{c+a}}{x^b} \bigg)^{c-a} }}}$

${\tiny{\implies}{\small{\sf{ \bigg( \dfrac{x^{a+b(a-b)}}{x^{c(a-b)}} \bigg) × \bigg( \dfrac{ x^{b+c(b-c)}}{x^{a(b-c)}} \bigg) × \bigg( \dfrac{x^{c+a(c-a)}}{x^{b(c-a) }}\bigg)}}}}$

${\tiny{\implies}}{\small{\sf{ \bigg( \dfrac{x^{a^2 - b^2}}{x^{ac-bc}} \bigg) × \bigg( \dfrac{x^{b^2 - c^2}}{x^{ab-ac}} \bigg) × \bigg( \dfrac{x^{c^2 - a^2}}{x^{bc-ab}} \bigg)}}}$

${\tiny{\implies}}{\small{\sf{ \bigg( \dfrac{ x^{a^2 - b^2 + b^2 - c^2 + c^2 - a^2}}{ x^{ac-bc+ab-ac+bc-ab}} \bigg) }}}$

${\tiny{\implies}}{\small{\sf{ \bigg( \dfrac{x^0}{x^0} \bigg) }}}$

${\tiny{\implies}}{\small{\sf{ \dfrac{1}{1}}}}$

${\tiny{\implies}}{\small{\bf{\underline{\boxed{\red{1}}}}}}$