F(z) =(| z|/+z) /2
is analytic at.
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Answer:
If z=x+iy
we have that
f(z)=|z|2=z⋅z¯¯¯=x2+y2
This shows that is a real valued function and can not be analytic.
We can rewrite the above as
f(z)=x2+y2+i⋅0
Set
u(x,y)=x2+y2
v(x,y)=0
Hence
f(x,y)=u(x,y)+i⋅v(x,y)
The function f is continuous because u,v are continuous. But Cauchy Riemann holds at the origin
ux=2x,uy=2y
ux=vy,uy=−vx
x=0,y=0=>z=0
Hence f is differentiable only at the origin, and the derivative is zero.
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