Question

फाइंड द एरिया ऑफ रेक्टेंगल हूज डाइमेंशंस आर 12cm एंड 5cm ​

Answer 1

$\underline\blue{\bold {Given \: Question :- }}$

• Find the area of rectangle whose dimensions are 12 cm and 5 cm.

__________________________________________

$\huge \orange{AηsωeR} ✍$

${ \boxed {\bf{Given}}}$

• Length of rectangle = 12 cm
• Breadth of rectangle = 5 cm

${ \boxed {\bf{To \: Find}}}$

• Area of rectangle

_____________________________________

☆Theory and Definition :-

• A rectangle is a two-dimensional plane figure with four sides. A rectangle is a four-sided polygon in which the opposite sides are parallel and equal to each other. It is one of the types of quadrilaterals in which all four angles are right angles or equal to 90 degrees.

Rectangle Properties :-

• A rectangle is a quadrilateral

• The opposite sides are parallel and equal to each other

• Each interior angle is equal to 90°.

• The sum of all the interior angles is equal to 360°.

• The diagonals bisect each other.

• Both the diagonals have the same length

• A rectangle with side lengths a and b has the perimeter as 2a+2b units

• A rectangle with side lengths a and b has the area as : ab square units

• The diagonals bisect each other at different angles. One is acute, and another one is an obtuse angle

__________________________________________

${ \boxed {\bf{Formula \: used :- }}}$

$\boxed{\bf \:  ⟼ Area\:of\:Rectangle=Length × Breadth}$

___________________________________________

${ \boxed {\bf{Solution}}}$

$\begin{gathered}\begin{gathered}\bf Let = \begin{cases} &\sf{l \: be \: the \: length \: of \: rectangle} \\ &\sf{b \: be \: the \: breadth \: of \: rectangle} \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\bf\red{According \: to \: statement}\end{gathered}$

$\begin{gathered}\bf\purple{Length \: of \: rectangle \: (l) = 12 \: cm}\end{gathered}$

$\begin{gathered}\bf\blue{Breadth \: of \: rectangle \: (b) = 5 \: cm}\end{gathered}$

$\bf \:{Area\:of\:Rectangle=Length × Breadth}$

$\bf \:  ⟼ \:{Area\:of\:Rectangle=12 × 5}$

$\bf \:  ⟼ \:{Area\:of\:Rectangle=60 \: {cm}^{2} }$

___________________________________________

$\large{\boxed{\boxed{\bf{Explore \ more : - }}}}$

☆ Basic Geometry Formulas

Perimeter of a Square = P = 4a

• Where a = Length of the sides of a Square

Perimeter of a Rectangle = P = 2(l+b)

• Where, l = Length ; b = Breadth

Area of a Square = A = a × a

• Where a = Length of the sides of a Square

Area of a Rectangle = A = l×b

• Where, l = Length ; b = Breadth

Area of a Triangle = A = ½×b×h

• Where, b = base of the triangle;
• h = height of the triangle

Area of a Trapezoid = A = ½×(x + y)×h

• Where x & y are the bases of the Trapezoid;
• h = height of the Trapezoid

Area of a Circle = A = π × r^2

Circumference of a Circle = A = 2πr

• Where, r = Radius of the Circle

___________________________________________