faactorise 27y³+125z³. please very urgent
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Answered by
4
plz mark as brainliest
here,
27 can be written as 3³
and 125 can be written as 5³
=(3y)³+(5z)³
by using the identity a³+b³=(a+b)(a²-ab+b²)
=(3y+5z)(9y²-15yz+25z²)
any doubt pls ask
here,
27 can be written as 3³
and 125 can be written as 5³
=(3y)³+(5z)³
by using the identity a³+b³=(a+b)(a²-ab+b²)
=(3y+5z)(9y²-15yz+25z²)
any doubt pls ask
Asvanthdora:
hi
Answered by
9
HELLO DEAR,
27Y³ + 125z³
(3y)³ + (5z)³
(3y + 5z)(9y² + 25z² - 15yz)
∴ [ (x³ + y³) = (x + y)(x² + y² - xyl]
I HOPE ITS HELP YOU DEAR,
THANKS
27Y³ + 125z³
(3y)³ + (5z)³
(3y + 5z)(9y² + 25z² - 15yz)
∴ [ (x³ + y³) = (x + y)(x² + y² - xyl]
I HOPE ITS HELP YOU DEAR,
THANKS
nice to meet u
:-)♥️
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