Math, asked by sreehari3507, 1 year ago

Fabina borrows rs 12500at12%per annum fr 3years at si and radha borrows the same amount fr same time period at 10%per annum compound annualy.Who pays more intrest and by how much

Answers

Answered by linkan58
1
SI is 4500 and CI is 9100 .
So the answer is 4600.
Answered by Anonymous
0

Given:

→ Fabiana borrows ₹ 12,500 at 12% per annum for 3 years at simple interest and Radha borrows the same amount for the same time period at 10% per annum, compounded annually.

Find:

→ Who pays more interest and by how much?

Using formula:

→ S.I = (Principal × Rate × Time)/100

→ A = Principal (1 + Rate/100)ⁿ

→ C.I = Amount - Principal

Note:

→ (ⁿ) = Number of years or Time period.

Calculations:

★ Finding for Radha:

→ (12500 × 12 × 3)/100

→ 450000/100

→ 4500

★ Finding for Fabina:

→ 12500 × (1 + 10/100)³

→ 12500 × (11/10)³

→ {12500 (11 × 11 × 11)}/1000

→ 125 × 1331/10

→ 166375/10

→ 16637.5

★ Amount paid by Radha:

→ 16637.50 - 12500

→ 4137.5

★ Fabia pays more:

→ 4500 - 4137.50

→ 362.5

Hence, Fabia pays more 362.5 than Radha.

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