Question

factarise 4x2 + y2 +z2-4xy-2yz+4xz​

Answer 1

Answer:

${(2x)}^{2} + { (- y)}^{2} + {z}^{2} + 2(2x)( - y) + 2( - y)(z) + 2(2x)(z)$

$= {(2x - y + z)}^{2}$

since (a+b+c)^2=a2+b2+c2+2ab+2bc+2ca

Answer 2

=(2x) ²+(-y) ²+z²+2(2x) (-y) +2(-y) (z) +2(2x) (x)

=(2x-y+z) ²

since (a+b+c)²=a²+b²+c²+2ab+2bc+2ca