Facters of 4ysquare minus 4y plus 1 is
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Answer:
(2y−1) ^²
Step-by-step explanation:
We know,
4y^²−2y+1
=(2y)^²−2(2y)(1)+(1)^²
We know appropriate identities x^²−2xy+y=(x−y)^²
Here x=2y and y=1, then
4y^²−4y+1= (2y−1) ^²
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