Question

factoeise x3-3x3-x+3

Answer 1

Given x3 + 1/x3 + 3x + 3/x. This can be re- written as shown x3 + 1/x3 + 3x2 × (1/x) + 3 × ( x) × (1/x) This is in the form of a3 + b3 +3a2b + 3ab2 = (a + b)3. Hence, x3 + 1/x3 + 3x2 ...

Answer 2

Hey!!!....Here is ur answer

x^3-3x^2-x+3

put x=1

(1)^3-3 (1)^2-1+3=0

so one factor is (x-1)

Now we find second factor..

x^3-3x^2-x+3/x-1

x^2-2x-3

x^2-3x+x-3

x (x-3)+1 (x-3)

(x-3)(x+1)

So the factor of x^3-3x^2-x+3 is (x-1)(x-3)(x+1)

Hope it will help you