Math, asked by khushi02022010, 6 months ago

Factor: 16w3 – u4w3​

Answers

Answered by Anonymous
4

 \huge\underline\mathfrak{\pink{Solution }}

16w3 – u4w3.

= w3(16 – u4).

= w3(42 - ((u2)2).

= w3(4 + u2)(4 - u2).

= w3(4 + u2)(22 - u2).

= w3(4 + u2)(2 + u)(2 - u).

Answer: w3(4 + u2)(2 + u)(2 - u).

Answered by ItzDeadDeal
1

\huge\underline\mathfrak{\red{Solution }}

16w3 – u4w3.

= w3(16 – u4).

= w3(42 - ((u2)2).

= w3(4 + u2)(4 - u2).

= w3(4 + u2)(22 - u2).

= w3(4 + u2)(2 + u)(2 - u).

Answer: w3(4 + u2)(2 + u)(2 - u).

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