Question

Factor: 3x^4y^3 – 48y^3.​

Answer 1

Answer:

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Step-by-step explanation:

3x^4y^3– 48y^3.

= 3y^3(x^4 – 16).

= 3y^3[(x^2)^2 - 4^2].

= 3y^3(x^2 + 4)(x^2 - 4).

= 3y^3(x^2 + 4)(x^2 - 2^2).

= 3y^3(x^2 + 4)(x + 2)(x -2).

Answer: 3y^3(x^2 + 4)(x + 2)(x -2)

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Answer 2

To fectorise

=3x^4y^3 - 48y^3

=3y^3 (x^4 - 16)

=3y^3(x^2 + 4)(x^2 - 4)

=3y^2(x^2 + 4)(x - 2)(x + 2)