Question

The size of Al3+ is lower than of F

Answer 1

Answer:

yes

Explanation:

effective nuclear charge ofAl3+ is more than F and it becomes isoelectronic to Neon.

Hence,size of Al3+<F

Answer 2

Yes, the size of $Al^{+3}$ is smaller than F.

• As the charge on a species increases its size decreases.
• $Al^{+3}$ and F are isoelectronic species which means they have the same number of electrons but in the case of Al the nucleus strongly attracts the electrons more than F due to the +3 charge so, its size decreases.
• Hence the size of $Al^{+3}$ is smaller than F.