Question

Factor: 5x2 – 15x – 20.

(a) 5(x-4)(x+1),

(b) -2(x-4)(x+5),

(c) -5(x+4)(x-1),

(d) 5(x+4)(x+1).

Answer 1

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Answer 2

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☸ Required Answer is :-

✔ Given equation , 5x²-15x-20

➡ taking 5 as a common we get,5 (x²-3x+4)

Now the equation becomes,5 (x²-3x+4)

A.T.Q

➡. 5(x²-3x+4)

➡ 5(x²-4x+x+4)

➡ 5 [x(x-4) - 1(x-4)]

➡ 5 (x-4) (x-1).

Hence, the Answer is Option (A).


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