Question

Factor completely (4x^3-x^2)(16x-4)?

Answer 1

Solution:

(4x³-x²)(16x-4)

= [4x²(x-1)][4(4x-1)]

= (4x²)×4×(x-1)(4x-1)

= 16x²(x-1)(4x-1)

Therefore,

(4x³-x²)(16x-4)=16x²(x-1)(4x-1)

••••

Answer 2

Hey!

Refer the below attachment !

Thanks !