Question

factor of x²-7x + 12 is​

Answer 1

Answer:

x^2-4x-3x+12=0

x(x-4)-3(x-4)

(x-3)(x-4)

x=3&X=4

Answer 2

${x}^{2} - 7x + 12 = 0$

${x}^{2} - 4x - 3x + 12 = 0$

$x(x - 4) - 3(x - 4) = 0$

$(x - 3)(x - 4) = 0$

so,

$x = 3 \: or \: 4$