Question

Factor the difference of squares: 4x^12 – 9

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$4 {x}^{2} - 12 {x}^{2} + 9 = 0 \\ 4 {x}^{2} - (6 + 6) {x}^{2} + 9 = 0 \\ 4 {x}^{2} - (6 {x}^{2} ) - (6 {x}^{2} ) + 9 = 0 \\ 2 {x}^{2} (2 {x}^{2} - 3) - 3( 2 {x}^{2} - 3) = 0 \\ (2 {x }^{2} - 3)(2 {x}^{2} - 3) \\ 2 {x - 3}^{2} = 0 \: or \: 2 {x}^{2} - 3 = 0 \\ {x}^{2} = \frac{3}{2} or \: {x}^{2} = \frac{3}{2} \\ x = \sqrt{ \frac{3}{2} } \: or \: x = \sqrt{ \frac{3}{2} }$