Factor the expression completely over the complex numbers. y4−16
Answers
Answered by
31
Heya
y⁴ - 16
= (y²)² - (4)²
Using identity
a² - b² = (a + b)(a - b)
= (y² + 4)(y² - 4)
Hope this helps you.
Answered by
2
~*HEY FRIEND*~
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________I
y^4 -16
(y^2)^2 -(2)^2
using formula (a^2-b^2) =(a+b) (a-b)
(y^2 -4^2) (y^2 +4^2)
(y+4) (y-4) (y^2 +4^2)
HOPE IT WILL HELP YOU
~* THE ANSWER OF YOUR QUESTION IS..*~
✍✍✍✍✍✍✍✍________________________________________I
y^4 -16
(y^2)^2 -(2)^2
using formula (a^2-b^2) =(a+b) (a-b)
(y^2 -4^2) (y^2 +4^2)
(y+4) (y-4) (y^2 +4^2)
HOPE IT WILL HELP YOU
ravi7762:
hii
Similar questions