Question

Factor x2 + x – 42.

An x-method chart shows the product negative 42 at the top of x and 1 at the bottom of x. 7 is on the left side of x and negative 6 is on the right side.
Use the completed X diagram to replace the x-term in the trinomial with two x-terms.

x^2 + x – 42 = x^2 +____ – 42

Next, use double grouping to factor the four terms.

= x(___)–(x + 7)

= _______

To verify,______ the factors.

Answer 1

⭕☺️$</p><p>\huge {\underline {\underline {\mathbb {\blue {ANSWER}}}}}$☺️⭕

$x^2+x-42=0\\x^2+7x-6x-42=0\\x(x+7)-6(x+7)=0\\(x-6)(x+)=0$

$\Large\boxed{x=6,(-7)}$

hOpe this helps uh‼️☺️

@❣️$

Answer 2

Given; An x-method chart shows the product negative 42 at the top of x and 1 at the bottom of x. 7 is on the left side of x and negative 6 is on the right side.

To Find; the factors

Solution; It is given that An x-method chart shows the product negative 42 at the top of x and 1 at the bottom of x. 7 is on the left side of x and negative 6 is on the right side.

In this method we factories the by splitting the middle term

x^2 + x – 42

= x^2 +7x-6x – 42

Next, use double grouping to factor the four terms.

= x(x+7)–6(x + 7)

= (x+7)(x-6)

Hence the factors are x-7 and x-6