Math, asked by sajeenafha, 12 days ago

factorice 2x³+x²-2x-1​

Answers

Answered by afiya6619
0

Answer:

x2(2x+1)−1(2x+1)(x2−1)(2x+1)((x)−2(1)2)(2x+1)(x+1)(x−1)(2x+1)

Answered by snehaprajnaindia204
6

Answer:

{\bf{\large{\tt{\blue{FACTORISATION:}}}}}

 \\

2 {x}^{3}  +  {x}^{2}  - 2x - 1 \\  \\  =   {x}^{2} (2x + 1) - 1(2x + 1) \\  \\  = ( {x}^{2}  - 1) \times (2x + 1) \\  \\

= (x - 1)(x + 1)(2x + 1)

 {x}^{2}  - 1 = 0 \\  =  >  {x}^{2}  = 1 \\  =  > x = 1 \:  \:  \:  \\ or \\ x =  - 1

 \\

2x + 1 = 0 \\  =  > x =   \frac{ - 1}{2}

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