factorice using identities (a+b)^3 - ( a - b) ^3
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Answer:
Step-by-sWe know the identity a
3
−b
3
=(a−b)(a
2
+b
2
+ab)
Using the above identity, the equation a
3
−b
3
−a+b can be factorised as follows:
a
3
−b
3
−a+b=(a
3
−b
3
)−(a−b)={(a−b)[(a)
2
+(b)
2
+(a×b)]}−(a−b)= [(a−b)(a
2
+b
2
+ab)]−(a−b)
=(a−b)(a
2
+b
2
+ab−1)
Hence, a
3
−b
3
−a+b=(a−b)(a
2
+b
2
+ab−1)tep explanation:
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